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0=x^2+5x-40x
We move all terms to the left:
0-(x^2+5x-40x)=0
We add all the numbers together, and all the variables
-(x^2+5x-40x)=0
We get rid of parentheses
-x^2-5x+40x=0
We add all the numbers together, and all the variables
-1x^2+35x=0
a = -1; b = 35; c = 0;
Δ = b2-4ac
Δ = 352-4·(-1)·0
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1225}=35$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-35}{2*-1}=\frac{-70}{-2} =+35 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+35}{2*-1}=\frac{0}{-2} =0 $
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